Hot Tub Forum

Original => Hot Tub Forum => Topic started by: psalad on June 15, 2013, 03:45:30 pm

Title: Incremental water change
Post by: psalad on June 15, 2013, 03:45:30 pm
Is there a good reason why water can't be changed a little at a time?   Seems to me an incremental water change would work... No?
Title: Re: Incremental water change
Post by: Chas on June 16, 2013, 08:36:07 am
You will use far more water that way, but it does freshen up the water.

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Title: Re: Incremental water change
Post by: psalad on June 19, 2013, 02:15:31 am
You will use far more water that way, but it does freshen up the water.

 8)

Why would I use more?  In this fantasy world of mine, I'm thinking I could change out 10 percent each week rather than changing out the full tub in 10 weeks.  Same difference water wise...
Title: Re: Incremental water change
Post by: wmccall on June 19, 2013, 07:30:32 am
There is at least two aspects to this ,but two come to mind.   TSD or total dissolved solids. After 10 years of tub ownership, I am pretty good at keeping my water clean and clear, but TSD is unavoidable.  In the middle of winter when I don't want to drain my tub, I'll quickly take out 50-100 gallons and then get out a short hose that just reaches the tub and replace it.  That helps me get through the winter.

But if your tub has organic contaminants, the replaced water just gets contaminated back again.  Another reason for the partial change, I use the minutes when the water level is down to scrub around the water line.
Title: Re: Incremental water change
Post by: chem geek on June 19, 2013, 05:15:53 pm
Why would I use more?  In this fantasy world of mine, I'm thinking I could change out 10 percent each week rather than changing out the full tub in 10 weeks.  Same difference water wise...

You use more water with incremental changes in order to get to the same level of water dilution (freshness).  If you replace all the water at once, then you get 100% fresh water.  If you replace only 10% of it and do this 10 times, then the replacement water mixes with the older water so you lose some of this freshening effect each time as follows:

1st 10%: 10% fresh + 90% old = 90% old overall
2nd 10%: 10% fresh + 90% of 90% old = 90%*90% = 81% old overall
3rd 10%: 90%*81% = 72.9% old overall
4th 10%: 90%*72.9% = 65.61% old overall
5th 10%: 90%*65.61% = 59.049% old overall
6th 10%: 90%*59.049% = 53.1441% old overall
7th 10%: 90%*53.1441% = 47.82969% old overall
8th 10%: 90%*47.82969% = 43.046721% old overall
9th 10%: 90%*43.046721% = 38.7420489% old overall
10th 10%: 90%*38.7420489% = 34.86784401% old overall

The faster general formula for incremental water changes such as this one is (1 - x)^(1/x) where "x" is the fraction of water that is changed, so 0.10 in this case so (1 - 0.10)^(1/0.10) = 0.9^10 = 34.86784401%

If you were to do continual water dilution with perfect mixing, then after using one full volume of water  you would have e^(-1) = 36.78794% old water.  So diluting only 10% at a time is nearly as imperfect as continual water dilution.

If you were to dilute by 50% in two steps then you would have:

1st 50%: 50% fresh + 50% old = 50% old overall
2nd 50%: 50% fresh + 50% of 50% old = 25% old overall

So you can see how rapidly water dilution becomes less effective unless you do it all at once and that there is a limit if you do it continuously.
Title: Re: Incremental water change
Post by: Chas on June 20, 2013, 08:40:02 am
I was JUST going to say that!  ;D :D




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